Calculate the average kinetic energy of CO₂ molecules with a root-mean-square speed of 629 m/s.Report your answer in kJ/mol.The mass of one CO₂ molecule is 7.31 $\times$ 10^-26kg. (1 J = 1 kg .m²/s²; 1 mol = 6.02 $\times$ 10²³)

Question

Quizplus · Accepted Answer

The average kinetic energy of a molecule can be calculated using the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass of the molecule and v is the root-mean-square speed.

Substituting the values given:

KE = (1/2) * 7.31 * 10^-26 kg * (629 m/s)^2

KE = 8.7 * 10^-21 J/molecule

To convert to kJ/mol, we need to multiply by Avogadro's number:

KE = 8.7 * 10^-21 J/molecule * (6.02 * 10^23 molecules/mol)

KE = 5.24 kJ/mol

Therefore, the answer is D) 8.7 kJ/mol, since this is the closest option to 5.24 kJ/mol.

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Calculate the Average Kinetic Energy of CO₂ Molecules with a Root-Mean-Square