What force is exerted by exactly one atmosphere of pressure (1.013 $\times$ 10⁵ Pa)on a mercury barometer with an inner diameter of 20.00 mm? Recall that the area of a circle is A = $\pi$r²,1 N = 1 kg m/s²,and 1 Pa = 1 N/m².

Question

Quizplus · Accepted Answer

The force exerted by the atmosphere on the mercury in the barometer is equal to the weight of the mercury column. The weight of the mercury column is equal to the density of mercury times the volume of the mercury column times the acceleration due to gravity. The volume of the mercury column is equal to the area of the cross-section of the barometer times the height of the mercury column. The area of the cross-section of the barometer is equal to pi times the radius of the barometer squared. The radius of the barometer is equal to 10.00 mm. The height of the mercury column is equal to 760 mm. The density of mercury is equal to 13.6 g/cm^3. The acceleration due to gravity is equal to 9.8 m/s^2.Therefore, the force exerted by the atmosphere on the mercury in the barometer is equal to:F = (13.6 g/cm^3) * (pi * (10.00 mm)^2) * (760 mm) * (9.8 m/s^2) = 31.82 NTherefore, the correct answer is A.

What Force Is Exerted by Exactly One Atmosphere of Pressure ×\times×

What Force Is Exerted by Exactly One Atmosphere of Pressure $\times$