What will be the final temperature of a 10.0 g piece of iron [C_p = 25.09 J/(mol.°C)] initially at 25°C,if it is supplied with 9.5 J from a stove?

Question

Quizplus · Accepted Answer

We can use the formula q = m*c*ΔT to calculate the change in temperature of the iron, where q is the heat supplied to the iron, m is the mass of the iron, c is the specific heat of iron, and ΔT is the change in temperature.

Rearranging the formula, we can solve for ΔT:

ΔT = q/(m*c)

Plugging in the given values, we get:

ΔT = 9.5 J / (10.0 g * 25.09 J/(mol*K) * (55.85 g/mol))

ΔT = 0.00716 K

Therefore, the final temperature of the iron is:

Tfinal = Tinitial + ΔT

Tfinal = 25°C + 0.00716 K

Tfinal = 27°C

Therefore, the best choice is B) 27°C, as this is the final temperature of the iron after being supplied with 9.5 J of heat.

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