A 3.0 $\times$ 10² kg black bear hibernates in the winter.During hibernation the bear's body temperature drops from 37.0 to 31.0°C.About how many grams of glucose must the bear metabolize to restore its body temperature to normal? Assume the bear's body is mostly water with a specific heat capacity of 4.18 J/(g.°C)and that all the energy from the combustion of glucose is used to raise the bear's body temperature.(Glucose: $\Delta$H_comb = -2808 kJ/mol,molar mass = 180 g/mol) C₆H₁₂O₆(g)+ 6 O₂(g)$\to$ 6 CO₂(g)+ 6 H₂O( )

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The Answer of A 3.0 $\times$ 10² kg black bear hibernates in the winter.During hibernation the bear's body temperature drops from 37.0 to 31.0°C.About how many grams of glucose must the bear metabolize to restore its body temperature to normal? Assume the bear's body is mostly water with a specific heat capacity of 4.18 J/(g.°C)and that all the energy from the combustion of glucose is used to raise the bear's body temperature.(Glucose: $\Delta$H_comb = -2808 kJ/mol,molar mass = 180 g/mol) C₆H₁₂O₆(g)+ 6 O₂(g)$\to$ 6 CO₂(g)+ 6 H₂O( )

A 30 ×\times× 102 Kg Black Bear Hibernates in the Winter Δ\DeltaΔ

A 30 $\times$ 10² Kg Black Bear Hibernates in the Winter $\Delta$