How many grams of iron(III)hydroxide (106.9 g/mol)will precipitate if excess iron(III)nitrate is added to 0.850 L of 1.26 M sodium hydroxide?

Question

Quizplus · Accepted Answer

First, write the balanced chemical equation for the reaction:

Fe(NO3)3 (aq) + 3 NaOH (aq) → Fe(OH)3 (s) + 3 NaNO3 (aq)

Next, use stoichiometry to determine how many moles of Fe(OH)3 will form:

1.26 mol/L NaOH × 0.850 L = 1.07 mol NaOH

Since there is a 1:1 ratio between NaOH and Fe(OH)3 in the balanced equation, there will be 1.07 mol Fe(OH)3 formed.

Finally, use the molar mass of Fe(OH)3 to convert from moles to grams:

1.07 mol Fe(OH)3 × 106.9 g/mol = 114 g Fe(OH)3

Therefore, the answer is B) 38.2 g.

How Many Grams of Iron(III)hydroxide (106