If 12.8 g lead(II)sulfate (303.3 g/mol)precipitates when excess potassium chloride is added to 1.65 L of a water sample,what is molar concentration of Pb²⁺ in the sample?

Question

Quizplus · Accepted Answer

The moles of PbSO4 are calculated by dividing the mass (12.8 g) by its molar mass (303.3 g/mol), resulting in 0.0422 moles. The molar concentration of Pb²⁺ is then found by dividing the moles of PbSO4 by the volume of the solution in liters (1.65 L), giving 0.0256 M.

If 128 G Lead(II)sulfate (303