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Potassium Perchlorate (KClO3)oxidizes Sucrose (C12H22O11)according to the Following Unbalanced Reaction \to

Question 31

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Potassium perchlorate (KClO3) oxidizes sucrose (C12H22O11) according to the following unbalanced reaction.What are the coefficients in the balanced chemical equation in the order in which it is written? KClO3(s) + C12H22O11(s) \to KCl(s) + CO2(g) + H2O  Potassium perchlorate (KClO<sub>3</sub>) oxidizes sucrose (C<sub>12</sub>H<sub>22</sub>O<sub>11</sub>) according to the following unbalanced reaction.What are the coefficients in the balanced chemical equation in the order in which it is written? KClO<sub>3</sub>(s) + C<sub>12</sub>H<sub>22</sub>O<sub>11</sub>(s)  \to  KCl(s) + CO<sub>2</sub>(g) + H<sub>2</sub>O   A) 4,1,4,12,11 B) 4,1,4,12,22 C) 2,1,2,12,11 D) 8,1,8,12,11 E) 8,2,8,12,11


A) 4,1,4,12,11
B) 4,1,4,12,22
C) 2,1,2,12,11
D) 8,1,8,12,11
E) 8,2,8,12,11

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