Copper(II)sulfate (CuSO₄)can be used to control algae growth.Aqueous CuSO₄ solutions that come in contact with the surface of galvanized (zinc-plated)steel pails undergo the following reaction: CuSO₄(aq)+ Zn(s)$\to$ Cu(s)+ ZnSO₄(aq) How many grams of zinc would react with 454 g (1 lb)of CuSO₄ (160 g/mol)?

Question

Quizplus · Accepted Answer

From the balanced chemical equation, the mole ratio between CuSO4 and Zn is 1:1. Therefore, 454 g CuSO4 (1 lb) is equal to 2.84 moles. To react completely with this amount of CuSO4, we need 2.84 moles of Zn. 
Using the molar mass of CuSO4 (160 g/mol), we can calculate that the weight of 2.84 moles of CuSO4 is 454 g. 
Therefore, we need 2.84 moles or 186 g of zinc to react with 454 g of CuSO4. 
The correct answer is B) 186 g.

Copper(II)sulfate (CuSO4)can Be Used to Control Algae Growth →\to→ Cu(s)+ ZnSO4(aq) How Many Grams of Zinc Would React with That

Copper(II)sulfate (CuSO₄)can Be Used to Control Algae Growth $\to$ Cu(s)+ ZnSO₄(aq)
How Many Grams of Zinc Would React with That