Suppose a bar code scanner emits light in the visible region of the spectrum at 4.62 $\times$ 10¹⁴ s^-1.What color is the light?

Question

Quizplus · Accepted Answer

The wavelength of the light is 4.62 x 10^-14 s, which is in the visible region of the spectrum. The color of the light can be determined using the following formula:wavelength (nm) = (speed of light (m/s)) / (frequency (Hz))The speed of light is 3 x 10^8 m/s, and the frequency is 4.62 x 10^14 Hz. Plugging these values into the formula, we get:wavelength (nm) = (3 x 10^8 m/s) / (4.62 x 10^14 Hz) = 652 nmThis wavelength corresponds to the color red.

Suppose a Bar Code Scanner Emits Light in the Visible ×\times×

Suppose a Bar Code Scanner Emits Light in the Visible $\times$