Light intensity ( I ) can be described as the power emitted by a light source (P) over a given area (in m2) .Suppose a 100-watt mercury vapor lamp emits 365.4 nm photons equally in all directions.At a distance of 1.450 m,how many photons hit per square meter per second? (1 watt = 1 J/s; I = P/Area = P/4 d 2,where d is the distance)
A) 5 107 photons
B) 7 109 photons/m2 .s
C) 9 1016 photons/m2 .s
D) 7 1018 photons/m2 .s
E) 6 1019 photons/m2 .s
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