Cyanidin Chloride (C₁₅H₁₁O₆Cl,322 $\times$ 10¹ Mol
B)3 $\times$ 10^-2 Mol
C)2 $\times$ 10^-2 Mol
D)2

Cyanidin chloride (C₁₅H₁₁O₆Cl,322.7 g/mol) contains the cyanidin ion,a pigment found in many berries.Calculate the number of moles of cyanidin chloride equivalent to 7.2 mg.

A) 2.2 $\times$ 10¹ mol
B) 3.2 $\times$ 10^-2 mol
C) 2.2 $\times$ 10^-2 mol
D) 2.2 $\times$ 10^-5 mol
E) 7.2 $\times$ 10^-5 mol