One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.93 liters against a constant external pressure of 1.00 atm.How much work (in joules)is performed on the surroundings? Ignore significant figures for this problem.(T = 300 K;1 L·atm = 101.3 J)

Question

Quizplus · Accepted Answer

The work done on the surroundings can be calculated using the formula W = -PextΔV, where Pext is the external pressure and ΔV is the change in volume. Plugging in the values given, we get W = -(1.00 atm)(7.93 L) x (101.3 J/L·atm) = -803 J. Since the gas is doing work on the surroundings, the work done is negative. Therefore, the answer is B) 803 J.

One Mole of an Ideal Gas Is Expanded from a Volume