Given: Cu₂O(s)+ O₂(g)$\times$2CuO(s) $\quad $$\Delta$H° = -144 kJ Cu₂O(s)$\times$ Cu(s)+ CuO(s) $\quad $ $\quad $ $\quad $ $\quad $$\Delta$H° = +11 kJ Calculate the standard enthalpy of formation of CuO(s).

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The Answer of Given: Cu₂O(s)+ O₂(g)$\times$2CuO(s) $\quad $$\Delta$H° = -144 kJ Cu₂O(s)$\times$ Cu(s)+ CuO(s) $\quad $ $\quad $ $\quad $ $\quad $$\Delta$H° = +11 kJ Calculate the standard enthalpy of formation of CuO(s).

Given: Cu2O(s)+ O2(g) ×\times× 2CuO(s) \quad Δ\DeltaΔ H° = -144 KJ Cu2O(s)

Given: Cu₂O(s)+ O₂(g) $\times$ 2CuO(s) $\quad$ $\Delta$ H° = -144 KJ
Cu₂O(s)