A gas sample is heated from -20.0°C to 57.0°C and the volume is increased from 2.00 L to 4.50 L.If the initial pressure is 0.140 atm,what is the final pressure?
A)0.0477 atm
B)-0.177 atm
C)0.411 atm
D)0.242 atm
E)0.0811 atm

Question

Quizplus · Accepted Answer

Using the combined gas law, (P1V1/T1) = (P2V2/T2), where temperatures are in Kelvin. Convert temperatures to Kelvin: T1 = 253.15 K, T2 = 330.15 K. Solve for P2: P2 = (P1V1T2)/(V2T1) = (0.140 atm * 2.00 L * 330.15 K) / (4.50 L * 253.15 K) = 0.0811 atm.

A Gas Sample Is Heated from -20