An analytical procedure requires a solution of chloride ions.How many grams of NaCl must be dissolved to make 1.95 L of 0.0561 M Cl^-?

Question

Quizplus · Accepted Answer

We can start by using the formula:

Molarity = moles of solute / volume of solution in liters

We know the molarity of chloride ions is 0.0561 M, and we want to find the amount of NaCl needed to make 1.95 L of this solution.

First, we need to determine the number of moles of chloride ions we need:

0.0561 M x 1.95 L = 0.109155 moles Cl-

Since NaCl is a 1:1 electrolyte, there will be the same number of moles of NaCl as there are chloride ions. Therefore, we need 0.109155 moles of NaCl.

Finally, we can use the molar mass of NaCl (58.44 g/mol) to calculate the mass needed:

0.109155 moles x 58.44 g/mol = 6.39 g NaCl

Therefore, the best choice is C) 6.39 g.

An Analytical Procedure Requires a Solution of Chloride Ions