A student weighs out 0.512 g of KHP (molar mass = 204.22 g/mol)and titrates to the equivalence point with 36.78 mL of a stock NaOH solution.What is the concentration of the stock NaOH solution? KHP is an acid with one acidic proton.

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of KHP using its formula weight:

0.512 g / 204.22 g/mol = 0.00251 mol KHP

Since KHP is a monoprotic acid, every mole of KHP reacts with one mole of NaOH. Therefore, the number of moles of NaOH in the titrant is also 0.00251 mol.

Next, we can use the volume and number of moles of NaOH to calculate its concentration:

0.00251 mol NaOH / 0.03678 L = 0.0682 M NaOH

Therefore, the concentration of the stock NaOH solution is 0.0682 M, which corresponds to answer choice D.

A Student Weighs Out 0