How many atoms of hydrogen are present in 7.63 g of ammonia? A)2.70 $\times$ 10²³ B)1.52 $\times$ 10²⁴ C)1.38 $\times$ 10²⁵ D)8.09 $\times$ 10²³ E)1.12 $\times$ 10²⁰

Question

Quizplus · Accepted Answer

To find the number of hydrogen atoms in 7.63 g of ammonia (NH3), first, calculate the number of moles of NH3 using its molar mass (17.03 g/mol). $7.63 \, \text{g} \div 17.03 \, \text{g/mol} = 0.448 \, \text{moles of NH3}$. Each molecule of NH3 contains 3 hydrogen atoms, so $0.448 \, \text{moles} \times 3 = 1.344 \, \text{moles of H}$. Since 1 mole of any substance contains $6.022 \times 10^{23}$ entities (Avogadro's number), $1.344 \, \text{moles} \times 6.022 \times 10^{23} = 8.09 \times 10^{23}$ hydrogen atoms.

How Many Atoms of Hydrogen Are Present in 7 ×\times× 1023 B)1

How Many Atoms of Hydrogen Are Present in 7 $\times$ 10²³
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