The rate constant for the beta decay of thorium-234 is 2.882 $\times$ 10^-² / day.What is the half-life of this nuclide?

Name: The rate constant for the beta decay of thorium-234 is 2.882 $\times$ 10 - 2 / day.What is the half-life of this nuclide?
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Quizplus · Accepted Answer

The half-life (t₁/₂) is calculated using the formula t₁/₂ = 0.693 / k, where k is the rate constant. Substituting the given rate constant, t₁/₂ = 0.693 / 0.02882 ≈ 24.05 days.

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