The rate constant for the decay of is 4.234 $\times$ 10^-³ / day.What is the half-life of A)81.84 days B)163.7 days C)327.4 days D)409.2 days E)none of these

Question

Quizplus · Accepted Answer

The half-life of a radioactive substance can be calculated using the formula: 
t1/2 = ln(2)/k 
where k is the rate constant.

Substituting the given value of k:

t1/2 = ln(2)/(4.234*10^10 S-1U-1P-1S-1S-1P0S-1U-1P13S-1S-1P0/day)

t1/2 = (0.693)/(4.234*10^10 S-1U-1P-1S-1S-1P0S-1U-1P13S-1S-1P0/day) 
t1/2 ≈ 163.7 days

Therefore, the correct answer is B) 163.7 days.

The Rate Constant for the Decay of Is 4 ×\times×

The Rate Constant for the Decay of Is 4 $\times$