The bismuth-209 nucleus has a binding energy per nucleon of 7.6514 MeV.(1 MeV is 1.60 $\times$ 10^-¹³ J).Determine the difference in mass between one mole of bismuth-209 nuclei and the component nucleons of which it is made. A)1.71 $\times$ 10^-³ kg B)3.92 $\times$ 10^-⁸ kg C)8.20 $\times$ 10^-⁶ kg D)2.56 $\times$ 10^-¹⁰ kg E)6.81 $\times$ 10^-⁴ kg

Question

Quizplus · Accepted Answer

The mass defect can be calculated using the binding energy per nucleon and the number of nucleons. For bismuth-209, with a binding energy per nucleon of 7.6514 MeV and Avogadro's number (6.022 × 10^23 nucleons/mol), the total binding energy for one mole of bismuth-209 nuclei can be calculated and then converted to mass using E=mc^2. The correct calculation leads to a mass difference of 1.71 × 10^-3 kg.

The Bismuth-209 Nucleus Has a Binding Energy Per Nucleon of 7.6514