A cell is set up with copper and lead electrodes in contact with CuSO₄(aq) and Pb(NO₃) ₂(aq) ,respectively,at 25°C.The standard reduction potentials are: Pb²⁺ + 2e^- $\to$ Pb
$\varepsilon$ ° = -0.13 V
Cu²⁺ + 2e^- $\to$ Cu
$\varepsilon$ ° = +0.34 V
If sulfuric acid is added to the Pb(NO₃) ₂ solution,forming a precipitate of PbSO₄,the cell potential:

Question

A cell is set up with copper and lead electrodes in contact with CuSO₄(aq) and Pb(NO₃) ₂(aq) ,respectively,at 25°C.The standard reduction potentials are: Pb²⁺ + 2e^-

\to

Pb

\varepsilon

° = -0.13 V
Cu²⁺ + 2e^-

\to

Cu

\varepsilon

° = +0.34 V
If sulfuric acid is added to the Pb(NO₃) ₂ solution,forming a precipitate of PbSO₄,the cell potential:

Quizplus · Accepted Answer

The formation of PbSO₄ precipitate decreases the concentration of Pb²⁺ ions, shifting the equilibrium and increasing the cell potential according to Le Chatelier's principle.

A Cell Is Set Up with Copper and Lead Electrodes →\to→

A Cell Is Set Up with Copper and Lead Electrodes $\to$