If the change in entropy of the surroundings for a process at 431 K and constant pressure is -326 J/K,what is the heat flow absorbed by for the system?

Question

Quizplus · Accepted Answer

The heat flow absorbed by the system can be calculated using the formula ΔS_surroundings = -q_system/T, where ΔS_surroundings is the change in entropy of the surroundings, q_system is the heat flow absorbed by the system, and T is the temperature in Kelvin. Rearranging the formula gives q_system = -ΔS_surroundings * T. Substituting the given values, q_system = -(-326 J/K * 431 K) = 140,506 J, which is approximately 141 kJ.

If the Change in Entropy of the Surroundings for a Process