For a certain process at 355 K,$\Delta$G = -11.8 kJ and $\Delta$H = -9.2 kJ.Therefore,$\Delta$S for the process is

Question

Quizplus · Accepted Answer

The change in Gibbs free energy (∆G) is related to the change in enthalpy (∆H) and the change in entropy (∆S) by the equation ∆G = ∆H - T∆S, where T is the temperature in Kelvin. Rearranging the equation, we get ∆S = (-∆G + ∆H)/T. Substituting the values given in the problem, we get ∆S = (-(-11.8 kJ) + (-9.2 kJ))/(355 K) = 7.3 J/K mol. Therefore, the answer is B.

For a Certain Process at 355 K Δ\DeltaΔ G = -118 KJ And Process

For a Certain Process at 355 K $\Delta$ G = -118 KJ And Process