For a solution equimolar in HCN and NaCN,which statement is false?

Question

Quizplus · Accepted Answer

The statement B is false because the presence of NaCN, which shares the common ion CN-, actually suppresses the dissociation of HCN, leading to a lower concentration of H^+ ions than if HCN were in solution alone. This is due to the Le Chatelier's principle, where adding more of a product (in this case, CN-) shifts the equilibrium to the left, reducing the concentration of H^+ ions produced.

For a Solution Equimolar in HCN and NaCN,which Statement Is