A titration of 200.0 mL of 1.00 M H₂A was done with 1.38 M NaOH.For the diprotic acid H₂A,K_a1 = 2.5 $\times$ 10^-⁵,K_a2 = 3.1 $\times$ 10^-⁹.Calculate the pH after 100.0 mL of 1.38 M NaOH have been added.

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The Answer of A titration of 200.0 mL of 1.00 M H₂A was done with 1.38 M NaOH.For the diprotic acid H₂A,K_a1 = 2.5 $\times$ 10^-⁵,K_a2 = 3.1 $\times$ 10^-⁹.Calculate the pH after 100.0 mL of 1.38 M NaOH have been added.

A Titration of 200 ×\times× 10-5,Ka2 = 3 ×\times× 10-9

A Titration of 200 $\times$ 10^-⁵,K_a2 = 3 $\times$ 10^-⁹