Calculate the pH of a 0.13 M solution of HOCl,K_a = 3.5 $\times$ 10^-⁸. A)4.17 B)8.34 C)9.83 D)1.00 E)3.76

Question

Quizplus · Accepted Answer

The pH of a weak acid solution can be calculated using the formula pH = -log[H+], where [H+] is found using the expression [H+] = √(Ka * [HOCl]). Substituting the given values, [H+] = √(3.5 x 10^-8 * 0.13) = √(4.55 x 10^-9) ≈ 6.75 x 10^-5. Therefore, pH ≈ -log(6.75 x 10^-5) ≈ 4.17.

Calculate the PH of a 0 ×\times× 10-8

Calculate the PH of a 0 $\times$ 10^-⁸