The pH of a solution of 1.9 M H₂A (K_a1= 1.0 $\times$ 10^-⁶ and K_a2is 1.0 $\times$ 10^-¹⁰)is: A)10.00 B)5.72 C)11.14 D)2.86 E)none of these

Question

Quizplus · Accepted Answer

The pH is determined by the first dissociation constant (Ka1) since it is much larger than Ka2. Using the formula for weak acid pH: pH = 0.5 * (pKa1 - log C), where C is the concentration of the acid, we find pH ≈ 2.86.

The PH of a Solution of 1 ×\times× 10-6 and Ka2 is 1

The PH of a Solution of 1 $\times$ 10^-⁶ and K_a2is 1