Initially 2.0 moles of N2(g) and 4.0 moles of H2(g) were added to a 1.0-liter container and the following reaction then occurred: 3H2(g) + N2(g)
2NH3(g)
The equilibrium concentration of NH3(g) = 0.55 moles/liter at 700.°C.The value for K at 700.°C for the formation of ammonia is:
A) 1.0 10-1
B) 5.5 10-2
C) 5.5 10-3
D) 3.0 10-1
E) none of these
Correct Answer:
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