A 20.0-g sample of methyl alcohol (CH₃OH,molar mass = 32.04 g/mol)was dissolved in 43.3 g of water.The mole fraction of CH₃OH is: A)0.260 B)0.624 C)0.316 D)4.85 E)0.206

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Quizplus · Accepted Answer

The mole fraction of a component in a solution is calculated by dividing the moles of that component by the total moles of all components in the solution. First, calculate the moles of methyl alcohol (CH3OH) and water (H2O).Moles of CH3OH = mass / molar mass = 20.0 g / 32.04 g/mol = 0.624 molesMoles of H2O = mass / molar mass = 43.3 g / 18.015 g/mol = 2.403 molesTotal moles = moles of CH3OH + moles of H2O = 0.624 moles + 2.403 moles = 3.027 molesMole fraction of CH3OH = moles of CH3OH / total moles = 0.624 / 3.027 ≈ 0.206

A 200-G Sample of Methyl Alcohol (CH3OH,molar Mass = 32

A 200-G Sample of Methyl Alcohol (CH₃OH,molar Mass = 32