The vapor pressure of water at 90°C is 0.692 atm.What is the vapor pressure (in atm)of a solution made by dissolving 4.13 mole(s)of CsF(s)in 1.00 kg of water? Assume that Raoult's law applies.
A)0.644 atm
B)0.795 atm
C)0.602 atm
D)0.692 atm
E)none of these

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The Answer of The vapor pressure of water at 90°C is 0.692 atm.What is the vapor pressure (in atm)of a solution made by dissolving 4.13 mole(s)of CsF(s)in 1.00 kg of water? Assume that Raoult's law applies.
A)0.644 atm
B)0.795 atm
C)0.602 atm
D)0.692 atm
E)none of these

The Vapor Pressure of Water at 90°C Is 0