A superball is dropped from a height of 8 ft. Each time it strikes the ground after falling from a height of t ft. it rebounds to a height of $\frac { 3 } { 4 } t$ feet. How long does it take for the ball to come to rest? (Use $g = 32 \mathrm { ft } / \mathrm { s } ^ { 2 }$ .)

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The Answer of A superball is dropped from a height of 8 ft. Each time it strikes the ground after falling from a height of t ft. it rebounds to a height of $\frac { 3 } { 4 } t$ feet. How long does it take for the ball to come to rest? (Use $g = 32 \mathrm { ft } / \mathrm { s } ^ { 2 }$ .)

A Superball Is Dropped from a Height of 8 Ft 34t\frac { 3 } { 4 } t43​t

A Superball Is Dropped from a Height of 8 Ft $\frac { 3 } { 4 } t$