Dawson's Repair Service orders parts from an electronic company who advertises its parts o be no more than 2% defective. What is the probability that Bill Dawson finds 2 or more parts out of a sample of 50 to be defective?
A) Almost 100%
B) 0.0217
C) 0.1562
D) Almost 50%
E) 0.4783

Question

Quizplus · Accepted Answer

This is a binomial distribution problem since we are looking for the probability of a certain number of successes (defective parts) out of a fixed number of trials (50 parts). Using the binomial probability formula, P(X≥2) = 1 - P(X=0) - P(X=1), where X is the number of defective parts in a sample of 50. P(X=0) = (0.98)^50 ≈ 0.3585 and P(X=1) = 50(0.02)(0.98)^49 ≈ 0.4362. Plugging these into the formula gives P(X≥2) ≈ 1 - 0.3585 - 0.4362 ≈ 0.2053, which is closest to 0.1562 (answer choice C).

Dawson's Repair Service Orders Parts from an Electronic Company Who