The arrival of customers at a service desk follows a Poisson distribution. If they arrive at the rate of two every five minutes, what is the probability that no customers arrive in a five-minute period?
A) 0.7311
B) 0.3711
C) 0.1353
D) 0.16

Question

Quizplus · Accepted Answer

The mean rate of customers arriving in a 5-minute period is:

λ = (2/5) * 5 = 2

Using the Poisson probability formula, the probability of zero customers arriving in a 5-minute period is:

P(0) = (e^-2) * (2^0) / 0! = e^-2 = 0.1353

Therefore, the answer is (C) 0.1353.

The Arrival of Customers at a Service Desk Follows a Poisson