The current through two identical light bulbs connected in series is 0.25 A.The voltage across both bulbs is 110 V.The resistance of a single light bulb is
A)22 ohms.
B)44 ohms.
C)220 ohms.
D)440 ohms.
E)none of these

Question

Quizplus · Accepted Answer

In a series circuit, the current is the same through each component. Therefore, the current through each light bulb is 0.25 A.

The total voltage across both bulbs is 110 V, and we know that voltage is shared between the bulbs. Therefore, the voltage across a single bulb is half of that, or 55 V.

Using Ohm's Law (V = IR), we can find the resistance of a single bulb:

55 V = 0.25 A × R

R = 220 ohms

Therefore, the answer is (C) 220 ohms.

The Current Through Two Identical Light Bulbs Connected in Series