The change in momentum,in kg m/s,that occurs when a 1.0 kg ball travelling at 4.0 m/s strikes a wall and bounces back at 2.0 m/s is

Question

Quizplus · Accepted Answer

The change in momentum, Δp, can be calculated using the formula:

Δp = m(vf - vi)

where m is the mass of the ball, vf is the final velocity (after bouncing), and vi is the initial velocity (before bouncing).

Using the values given in the problem:

m = 1.0 kg
vf = 2.0 m/s
vi = 4.0 m/s

Δp = 1.0 kg * (2.0 m/s - 4.0 m/s) = -2.0 kg m/s

Note that the negative sign indicates that the direction of the change in momentum is opposite to the direction of the initial momentum.

However, we are only interested in the magnitude of the change in momentum, so we take the absolute value:

|Δp| = |-2.0 kg m/s| = 2.0 kg m/s

Therefore, the correct answer is C) 6) - the change in momentum is 2.0 kg m/s.

The Change in Momentum,in Kg M/s,that Occurs When a 1