The vertical height attained by a basketball player who achieves a hang time of a full 1 s is
A)about 0.8 m.
B)about 1 m.
C)about 1.2 m.
D)about 2.5 m.
E)more than 2.5 m.

Question

Quizplus · Accepted Answer

The vertical height attained by a basketball player during hang time can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.81 m/s^2), and t is the hang time (1 s). Plugging in the values, h = (1/2) * 9.81 * 1^2 = 4.905 m. However, the player does not achieve this entire height as some of it is used for the jump. On average, a basketball player can jump around half of their height, which is typically around 1.9 m. Therefore, the height attained during a 1 s hang time is about 1.2 m (4.905 m - 1.9 m = 3.005 m, which is divided by 2 to get the average jump height, and subtracted from the total height to get the hang time height). Therefore, the answer is option (C).

The Vertical Height Attained by a Basketball Player Who Achieves