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Hydrogen Reacts with Nitrogen to Form Ammonia (NH3) According to the Reaction

Question 62

Multiple Choice

Hydrogen reacts with nitrogen to form ammonia (NH3) according to the reaction
 Hydrogen reacts with nitrogen to form ammonia (NH<sub>3</sub>)  according to the reaction         The value of  \Delta H <sup> \circ </sup> is -92.38 kJ/mol, and that of  \Delta S <sup> \circ </sup> is -198.2 J/(mol . K) . Determine  \Delta G <sup> \circ </sup> at 25<sup> \circ </sup>C. A) (-5.897  \times  10<sup>4</sup> kJ/mol)  B) (-297.8 kJ/mol)  C) (-33.32 kJ/mol)  D) (-16.66 kJ/mol)  E) (+49.5 kJ/mol)   Hydrogen reacts with nitrogen to form ammonia (NH<sub>3</sub>)  according to the reaction         The value of  \Delta H <sup> \circ </sup> is -92.38 kJ/mol, and that of  \Delta S <sup> \circ </sup> is -198.2 J/(mol . K) . Determine  \Delta G <sup> \circ </sup> at 25<sup> \circ </sup>C. A) (-5.897  \times  10<sup>4</sup> kJ/mol)  B) (-297.8 kJ/mol)  C) (-33.32 kJ/mol)  D) (-16.66 kJ/mol)  E) (+49.5 kJ/mol)   Hydrogen reacts with nitrogen to form ammonia (NH<sub>3</sub>)  according to the reaction         The value of  \Delta H <sup> \circ </sup> is -92.38 kJ/mol, and that of  \Delta S <sup> \circ </sup> is -198.2 J/(mol . K) . Determine  \Delta G <sup> \circ </sup> at 25<sup> \circ </sup>C. A) (-5.897  \times  10<sup>4</sup> kJ/mol)  B) (-297.8 kJ/mol)  C) (-33.32 kJ/mol)  D) (-16.66 kJ/mol)  E) (+49.5 kJ/mol)
The value of Δ\Delta H \circ is -92.38 kJ/mol, and that of Δ\Delta S \circ is -198.2 J/(mol . K) . Determine Δ\Delta G \circ at 25 \circ C.


A) (-5.897 ×\times 104 kJ/mol)
B) (-297.8 kJ/mol)
C) (-33.32 kJ/mol)
D) (-16.66 kJ/mol)
E) (+49.5 kJ/mol)

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