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Calculate the Equilibrium Constant at 500 K for the Following ×\times

Question 139

Multiple Choice

Calculate the equilibrium constant at 500 K for the following reaction given the data below.
 Calculate the equilibrium constant at 500 K for the following reaction given the data below.        K <sub>c </sub>(298 K)  = 6.1  \times  10<sup>5</sup>   (NH<sub>3</sub>, g)  = -16.5 kJ/mol   (NH<sub>3</sub>, g)  = -46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4  \times  10<sup>-4</sup> E) 332  Calculate the equilibrium constant at 500 K for the following reaction given the data below.        K <sub>c </sub>(298 K)  = 6.1  \times  10<sup>5</sup>   (NH<sub>3</sub>, g)  = -16.5 kJ/mol   (NH<sub>3</sub>, g)  = -46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4  \times  10<sup>-4</sup> E) 332  Calculate the equilibrium constant at 500 K for the following reaction given the data below.        K <sub>c </sub>(298 K)  = 6.1  \times  10<sup>5</sup>   (NH<sub>3</sub>, g)  = -16.5 kJ/mol   (NH<sub>3</sub>, g)  = -46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4  \times  10<sup>-4</sup> E) 332 K c (298 K) = 6.1 ×\times 105  Calculate the equilibrium constant at 500 K for the following reaction given the data below.        K <sub>c </sub>(298 K)  = 6.1  \times  10<sup>5</sup>   (NH<sub>3</sub>, g)  = -16.5 kJ/mol   (NH<sub>3</sub>, g)  = -46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4  \times  10<sup>-4</sup> E) 332 (NH3, g) = -16.5 kJ/mol  Calculate the equilibrium constant at 500 K for the following reaction given the data below.        K <sub>c </sub>(298 K)  = 6.1  \times  10<sup>5</sup>   (NH<sub>3</sub>, g)  = -16.5 kJ/mol   (NH<sub>3</sub>, g)  = -46.1 kJ/mol A) 53 B) 1,800 C) 7.5 D) 5.4  \times  10<sup>-4</sup> E) 332 (NH3, g) = -46.1 kJ/mol


A) 53
B) 1,800
C) 7.5
D) 5.4 ×\times 10-4
E) 332

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