For an Equilibrium Reaction with K = 4 $\times$ 10^-3, the Reverse Rate Constant Was Found to Be 2

For an equilibrium reaction with K = 4.3 $\times$ 10^-3, the reverse rate constant was found to be 2.1 $\times$ 10². What is the value of the forward rate constant?

A) 2.0 $\times$ 10^-5
B) 3.1 $\times$ 10^-3
C) 9.0 $\times$ 10^-1
D) 4.9 $\times$ 10⁴
E) 5.3 $\times$ 10³