The second-order reaction A B is found to have a rate constant of 0.978 M ^-1s ^-1. What is the half-life of this reaction when [A]₀ = 0.0300 M ?

Question

Quizplus · Accepted Answer

The half-life of a second-order reaction is given by the equation:

t1/2 = 1 / (k [A]0)

Where k is the rate constant and [A]0 is the initial concentration of reactant. Substituting the given values:

t1/2 = 1 / (0.978 M-1 s-1 * 0.0300 M)

t1/2 = 34.1 s

Therefore, the correct choice is C.

The Second-Order Reaction a B Is Found to Have