What mass of potassium iodide (molar mass = 166.0 g/mol) is needed to produce 325.0 mL of a solution that has a concentration of 0.0150 M ?

Question

Quizplus · Accepted Answer

First, we need to use the formula:
concentration = moles of solute / volume of solution

We can rearrange this formula to solve for moles of solute:
moles of solute = concentration x volume of solution

Plugging in the given values, we get:
moles of solute = 0.0150 M x 0.3250 L = 0.00488 moles

Finally, we can use the molar mass of potassium iodide to convert moles to grams:
mass = moles x molar mass
mass = 0.00488 moles x 166.0 g/mol = 0.809 g

Therefore, the best choice is (B) 0.809 g.

What Mass of Potassium Iodide (Molar Mass = 166