What mass of barium sulfate (molar mass = 233 g/mol) is produced when 125 mL of a 0.150 M solution of barium chloride is mixed with 125 mL of a 0.150 M solution of iron(III) sulfate?
A) 7.59 g
B) 3.65 g
C) 13.1 g
D) 18.8 g
E) 4.37 g
Correct Answer:
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