Suppose two individuals with the genotype AaBbCc are mated. Assuming that the genes are not linked, what fraction of the offspring are expected to be homozygous recessive for the three traits?
A) 1/4
B) 1/8
C) 1/16
D) 1/64

Question

Quizplus · Accepted Answer

Each gene pair (Aa, Bb, Cc) segregates independently, and the probability of being homozygous recessive (aa, bb, cc) for each gene is 1/4. Therefore, the probability for all three traits is (1/4) * (1/4) * (1/4) = 1/64.

Suppose Two Individuals with the Genotype AaBbCc Are Mated