For the following Questions assume that the heights of American women ages 18 to 24 are normally distributed, with mean 64.5 inches and standard deviation 2.5 inches.
-About what percentage of American women ages 18 to 24 have heights greater than 69.5 inches?
A) 2.5%
B) 5%
C) 32%
D) 50%

Question

Quizplus · Accepted Answer

To find the percentage of women taller than 69.5 inches, we calculate the z-score: $z = \frac{69.5 - 64.5}{2.5} = 2$. Looking up a z-score of 2 in a standard normal distribution table, we find that about 97.5% of the area is to the left, meaning 2.5% is to the right, or taller than 69.5 inches.

For the Following Questions Assume That the Heights of American