Suppose that the discrete logistic model for population growth is models as follows: $P _ { n + 1 } = P _ { n } + 0.351 P _ { n } \left( 1 - \frac { P _ { n } } { 2.849 \times 10 ^ { 8 } } \right)$ What is the carrying capacity?

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The carrying capacity is the maximum population size that the environment can sustain. In this model, it is the value of P where the population growth rate becomes zero. Solving the equation $$0.351 P \left(1-\frac{P}{2.849 	imes 10^8}ight)=0$$ yields $P=0$ or $P=2.849 	imes 10^8$. The population cannot be negative so the carrying capacity is $2.849 	imes 10^8.$

Suppose That the Discrete Logistic Model for Population Growth Is Pn+1=Pn+0.351Pn(1−Pn2.849×108)P _ { n + 1 } = P _ { n } + 0.351 P _ { n } \left( 1 - \frac { P _ { n } } { 2.849 \times 10 ^ { 8 } } \right)Pn+1​=Pn​+0.351Pn​(1−2.849×108Pn​​)

Suppose That the Discrete Logistic Model for Population Growth Is $P _ { n + 1 } = P _ { n } + 0.351 P _ { n } \left( 1 - \frac { P _ { n } } { 2.849 \times 10 ^ { 8 } } \right)$