The contingency table for a sample of corporate executives classified by educational level and the social activity follows. What does the expected frequency for the "above average" social activity and "high school" education equal?
A)9.50
B)60.00
C)22.50
D)28.50

Question

The contingency table for a sample of corporate executives classified by educational level and the social activity follows.  What does the expected frequency for the "above average" social activity and "high school" education equal?
A)9.50 
B)60.00 
C)22.50 
D)28.50

Quizplus · Accepted Answer

To find the expected frequency for "above average" social activity and "high school" education, we need to first calculate the row and column totals. The row total for "high school" education is 20, and the column total for "above average" social activity is 45.

To find the expected frequency, we use the formula:

Expected frequency = (row total * column total) / sample size

In this case, the sample size is 80 (the total number of executives in the sample).

Expected frequency = (20 * 45) / 80 = 11.25

Therefore, the expected frequency for "above average" social activity and "high school" education equals 11.25, which is closest to option C (22.50).

The Contingency Table for a Sample of Corporate Executives Classified