The weights of a sample of crates ready for shipment to Moscow, Russia are (in kilograms): 103, 97, 101, 106, and 103. What is the mean deviation?
A)0 kg
B)6.9 kg
C)102.0 kg
D)2.4 kg

Question

Quizplus · Accepted Answer

1. Find the mean:
Mean = (103 + 97 + 101 + 106 + 103) / 5 = 102 kg
2. Find the deviation of each weight from the mean:
|103 - 102| = 1
|97 - 102| = 5
|101 - 102| = 1
|106 - 102| = 4
|103 - 102| = 1
3. Find the mean of the deviations:
Mean deviation = (1 + 5 + 1 + 4 + 1) / 5 = 2.4 kg
Therefore, the answer is D.

The Weights of a Sample of Crates Ready for Shipment