A rancher genotypes all of her 150 head of cattle. In her herd, 25 are A₁A₁, 75 are A₁A₂, and 50 are A₂A₂. Assuming there is random mating, no selection, no mutation, and no new cattle are introduced into the population, what is the probability that the A₁ allele will be fixed? A) 0 B) 0.4167 C) 0.6588 D) 1

Question

Quizplus · Accepted Answer

The probability of fixing a certain allele can be calculated using the Hardy-Weinberg equation: p(frequency of A₁ allele) = (number of A₁ alleles * 2 + number of heterozygous individuals) / (total number of alleles * 2) Using the information given in the question, we can calculate: p = (25 * 2 + 75) / (150 * 2) = 0.3333 Since there are only two alleles in this population (A₁ and A₂), the probability of fixing A₁ will be equal to p. Therefore, the probability of fixing A₁ is 0.3333 or approximately 0.4167.

A Rancher Genotypes All of Her 150 Head of Cattle