The distribution of weights of men in the American population is not symmetrical.Most weights are bunched together at the lower end of the distribution.As weights increase,there are fewer and fewer men with these weights.How would you describe the relationship between the mean,the median,and the mode in this distribution? (Hint: Drawing a picture of the distribution may be helpful. )
A)mode

Question

The distribution of weights of men in the American population is not symmetrical.Most weights are bunched together at the lower end of the distribution.As weights increase,there are fewer and fewer men with these weights.How would you describe the relationship between the mean,the median,and the mode in this distribution? (Hint: Drawing a picture of the distribution may be helpful. )
A)mode < median < mean
B)mean < median < mode
C)mean = median = mode
D)median < mode < mean

Quizplus · Accepted Answer

In a distribution that is skewed to the right (as described, with most weights bunched at the lower end and the tail extending to the right), the mode is at the highest peak (most common value), the median is the middle value when all are sorted, and the mean is pulled towards the tail. Thus, mode < median < mean.

The Distribution of Weights of Men in the American Population