Exhibit 11-6
In order to determine whether or not a particular medication was effective in curing the common cold, one group of patients was given the medication, while another group received sugar pills. The results of the study are shown below.
We are interested in determining whether or not the medication was effective in curing the common cold.
-Refer to Exhibit 11-6. The p-value is
A)less than .005
B)between .005 and .01
C)between .01 and .025
D)between .025 and .05

Question

Exhibit 11-6
In order to determine whether or not a particular medication was effective in curing the common cold, one group of patients was given the medication, while another group received sugar pills. The results of the study are shown below.
  We are interested in determining whether or not the medication was effective in curing the common cold.
-Refer to Exhibit 11-6. The p-value is
A)less than .005 
B)between .005 and .01 
C)between .01 and .025 
D)between .025 and .05

Quizplus · Accepted Answer

The p-value is the probability of obtaining the observed results or more extreme results assuming the null hypothesis is true. In this case, the null hypothesis is that there is no difference in effectiveness between the medication and the sugar pills. The alternative hypothesis is that the medication is effective in curing the common cold.

Using the formula for calculating the p-value, we find that it is less than .005. This means that there is strong evidence to reject the null hypothesis and accept the alternative hypothesis. Therefore, we can conclude that the medication was effective in curing the common cold.

Exhibit 11-6 In Order to Determine Whether or Not a Particular Medication